斐波那契数列
#include <stdio.h>
int main()
{
int i, n, t1 = 0, t2 = 1, nextTerm;

printf("输出几项: ");
scanf("%d", &n);

printf("斐波那契数列: ");

for (i = 1; i <= n; ++i)
{
printf("%d, ", t1);
nextTerm = t1 + t2;
t1 = t2;
t2 = nextTerm;
}
return 0;
}