533/*------------------------------------------------【程序设计】--------------------------------------------------功能：编写函数fun求s=1^k+2^k +3^k + ......+N^k的值， （1的K次方到N的K次方的累加和）。------------------------------------------------*/#define K 4#define N 5#include <stdio.h>long fun(int n,int k){ /**********Program**********/ int i,s,j,t; for(i=0;i<N;i++) { t=1; for(j=0;j<K;j++) t*=i+1; s=s+t; } return t; /********** End **********/ }main(){ long int sum; printf("Sum of %d powers of integers from 1 to %d = ",K,N); sum=fun(N,K); printf("%ld\n",sum); }