while(a!="%")进行报错 java.lang.NumberFormatException: For input string: "%"
at java.base/java.lang.NumberFormatException.forInputString(NumberFormatException.java:67)
at java.base/java.lang.Integer.parseInt(Integer.java:654)
at java.base/java.lang.Integer.parseInt(Integer.java:786)
at 实验.chap1_task1.main(chap1_task1.java:18)
改进后
while(!in.hasNext("%")