二元一次方程求解；
#include<stdio.h>
#include<math.h>
int main()
{
int a, b, c, x1, x2,D;
printf("a=");
scanf_s("%d", &a);
printf("b=");
scanf_s("%d",&b);
printf("c=");
scanf_s("%d", &c);
D = pow(b, 2) - 4 * a * c;
if (D >= 0)
x1 = (-b + sqrt(D)) / (2 * a),
x2 = (-b - sqrt(D)) / (2 * a),
printf("%d\n%d", x1, x2);
else
printf("无解\n");
return 0;
}
