#697 B
思路：简单模拟；
#include<stdio.h>
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
int n;
scanf("%d",&n);
int res=n/2020;
int y=n%2020;
if(y<=res)printf("YES\n");
else printf("NO\n");
}
return 0;
}